I'm not sure how to solve this problem: A cooler contains eleven bottles of sports drink: four lemonlime flavored and seven orange flavored. You randomly grab a bottle and give it to your friend. Then, you randomly grab a bottle for yourself. You and your friend both get lemonlime.Find the probability of this occurring.
Posted on Aug 06, 2017, by Mariarose4 
Posted on Aug 07, 2017, by
Jcalamari


the whole thing is the chance of taking a lemonline one first, then once again taking ANOTHER lemonline one out by chance :D
Posted on Aug 07, 2017, by
Jcalamari


that's what i meant by "so the chance of taking a lemonlime one first, then once again, is 4/11 times 3/10." thats the whole thing. sorry if it was confusing.
Posted on Aug 07, 2017, by
Jcalamari

the key is to imagine it as grabbing one bottle first. then it's a new situation, then you grab the second bottle.
the first bottle shouldn't be hard. there are four lemonlime drinks and 11 in all, so there's a 4/11 chance of getting a lemonlime first.
now we want the chance of that happening, AND taking a second bottle. so the whole chance is: 4/11 times the chance of taking a second bottle of lemonlime now.
the chance of taking the second bottle is found the same way. but i'll show u. well, we have already taken one lemonlime out. so there are just 3 lemonlime drinks and still 7 orange drinks (10 drinks left). so there is a 3/10 chance of taking a lemonlime one now.
so the chance of taking a lemonlime one first, then once again, is 4/11 times 3/10.
(4/11)*(3/10) = 12/110 = 6/55
hope this helped